x^2+5x-(2k+4)=0

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Solution for x^2+5x-(2k+4)=0 equation:


Simplifying
x2 + 5x + -1(2k + 4) = 0

Reorder the terms:
x2 + 5x + -1(4 + 2k) = 0
x2 + 5x + (4 * -1 + 2k * -1) = 0
x2 + 5x + (-4 + -2k) = 0

Reorder the terms:
-4 + -2k + 5x + x2 = 0

Solving
-4 + -2k + 5x + x2 = 0

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + -2k + 5x + 4 + x2 = 0 + 4

Reorder the terms:
-4 + 4 + -2k + 5x + x2 = 0 + 4

Combine like terms: -4 + 4 = 0
0 + -2k + 5x + x2 = 0 + 4
-2k + 5x + x2 = 0 + 4

Combine like terms: 0 + 4 = 4
-2k + 5x + x2 = 4

Add '-5x' to each side of the equation.
-2k + 5x + -5x + x2 = 4 + -5x

Combine like terms: 5x + -5x = 0
-2k + 0 + x2 = 4 + -5x
-2k + x2 = 4 + -5x

Add '-1x2' to each side of the equation.
-2k + x2 + -1x2 = 4 + -5x + -1x2

Combine like terms: x2 + -1x2 = 0
-2k + 0 = 4 + -5x + -1x2
-2k = 4 + -5x + -1x2

Divide each side by '-2'.
k = -2 + 2.5x + 0.5x2

Simplifying
k = -2 + 2.5x + 0.5x2

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